(1/8)^5x=32^x+8

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Solution for (1/8)^5x=32^x+8 equation: 



(1/8)^5x=32^x+8

We move all terms to the left:

(1/8)^5x-(32^x+8)=0



Domain of the equation: 8)^5x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/8)^5x-(32^x+8)=0

We get rid of parentheses

(+1/8)^5x-32^x-8=0

We multiply all the terms by the denominator


(+1-32^x*8)^5x-8*8)^5x=0

Wy multiply elements

(+1-32^x*8)^5x-64x=0

We add all the numbers together, and all the variables

-64x+(+1-32^x*8)^5x=0

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